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Unit 8: Electric Charges, Fields, and Gauss's Law

Conservation of Electric Charge and the Process of Charging

Explain how objects become charged by friction, contact, polarization and grounding, and use conservation of charge to track where every coulomb goes.

Topic 8.2 · 10 min read

Shuffle across a wool rug in rubber-soled shoes and touch a doorknob, and the spark you feel is electrons your soles scraped off the rug on the way. You came away negative, the rug positive, by exactly equal amounts. No charge was made: electrons moved from one object to the other, and the total stayed zero. That bookkeeping rule, charge conservation, together with the difference between conductors and insulators from topic 8.1, explains every way an object gets charged.

Charge is conserved

Pick a system: any object or collection of objects you choose to track, with everything else called its surroundings. The net charge of the system is the sum of the charges of everything in it, signs included.

In solids the charge that moves is almost always electrons. Protons are bound in nuclei, deep inside atoms, and stay put. So "an object became positive" means it lost electrons, and "it became negative" means it gained them. An object with charge +q+q is missing N=qeN = \frac{q}{e} electrons. (In liquids and gases whole ions can move, which is how charge flows through salt water or a spark, but the bookkeeping is the same.)

Conservation is not an approximation. In particle collisions, new charged particles do get created, but always in pairs whose charges sum to zero, such as an electron and a positron. No experiment has ever found the net charge of an isolated system changing.

Inside a system, charge can also rearrange without any crossing the boundary: the net charge stays the same while the charge distribution shifts, as it does whenever another charged object comes close (polarization, below).

Charging by friction and by contact

Friction. When two different materials touch, electrons at the contact points move from the material that holds them less tightly to the one that holds them more tightly. Rubbing makes many more contact points, so more electrons move. Rubber and plastic grab electrons from hair, wool and skin; glass rubbed with silk gives up electrons. The two objects end with charges that are equal in size and opposite in sign, because the electrons one lost are exactly the ones the other gained.

Contact. When a charged object touches a second object, some of its excess charge spreads onto the second. What happens next depends on the material.

  • On a conductor, the transferred charge spreads over the whole object, because charge carriers move freely and like charges push each other apart.
  • On an insulator, the charge stays near the spot where it landed. A plastic rod touched to a metal ball at one end gives up only the charge near its tip.

When two identical metal spheres touch, they end with equal charges: nothing distinguishes one sphere from the other, so the charge has no reason to prefer either. Each gets half the total. For example, spheres with +9.0 nC+9.0\ \text{nC} and −3.0 nC-3.0\ \text{nC} touch and separate with +3.0 nC+3.0\ \text{nC} each; the total, +6.0 nC+6.0\ \text{nC}, is unchanged. (Topic 10.2 handles spheres of different sizes, which do not share equally.)

Polarization: charge separation without transfer

A charged object can rearrange the charge in a nearby object without touching it. Its electric force pulls opposite charge toward it and pushes like charge away inside the second object. This induced charge separation is polarization, and it happens even if the second object is neutral overall.

  • In a conductor, free electrons move across the whole object. Bring a negative rod near one end of a neutral metal can and electrons flee to the far side, leaving the near side positive. The can's net charge is still zero.
  • In an insulator, electrons can't leave their atoms, but each atom's or molecule's electron cloud shifts slightly away from the negative rod (topic 8.1). The surface facing the rod ends up slightly positive and the far surface slightly negative.

Polarization explains why a charged object attracts neutral ones: a comb attracts bits of paper, a balloon sticks to a wall. The induced charge opposite to the rod's sits closer to the rod than the induced like charge, and the Coulomb force weakens with distance, so the attraction wins. For example, if a +10 nC+10\ \text{nC} rod induces −1.0 nC-1.0\ \text{nC} on the near side of a neutral object 5.0 cm5.0\ \text{cm} away and +1.0 nC+1.0\ \text{nC} on its far side 5.4 cm5.4\ \text{cm} away, the attraction is 3.6×10−5 N3.6\times10^{-5}\ \text{N} and the repulsion is 3.1×10−5 N3.1\times10^{-5}\ \text{N}, a net pull of 5×10−6 N5\times10^{-6}\ \text{N} toward the rod. A neutral object is attracted by a positive rod and by a negative rod alike.

That has a consequence for experiments: attraction can't tell you that an object is charged, because a neutral object is attracted too. Repulsion can. If an object is repelled by a rod known to be negative, the object must be negative.

Grounding and charging by induction

Grounding means connecting an object by a conductor (a wire, a metal pipe, a person) to Earth. Earth is so large, and so close to neutral, that it can supply or absorb any amount of electrons an everyday object needs without its own charge changing noticeably. It is a charge reservoir.

A grounded conductor with no other charges nearby ends up neutral: excess electrons flow to Earth, or missing electrons flow up from it. This is why fuel trucks are grounded before they pump, and why electronics workers wear grounded wrist straps. With a charged object nearby, a grounded conductor ends up with a net charge, which gives a way to charge an object without touching it with anything charged.

Four panels showing a metal sphere on an insulating stand being charged by induction. Panel 1: a negatively charged rod is held to the left of a neutral sphere; the sphere's left side shows plus signs and its right side minus signs. Panel 2: with the rod still near, a wire connects the sphere to ground; electrons flow from the sphere down to the ground, and only plus signs remain, on the left side. Panel 3: the ground wire is removed with the rod still near; the plus signs stay on the left side. Panel 4: the rod is taken away and the plus signs spread evenly over the sphere's surface, so the sphere is left positively charged.

Charging by induction, step by step, with a negative rod:

  1. Hold the rod near a neutral metal sphere on an insulating stand. Electrons in the sphere are pushed to the far side; the near side is left positive.
  2. Ground the sphere. Electrons, still repelled by the rod, now have somewhere farther to go: they flow down to Earth. It doesn't matter where on the sphere the ground wire touches, even the side nearest the rod; the whole sphere is one conductor.
  3. Disconnect the ground while the rod is still near. The electrons that left can't come back.
  4. Remove the rod. The sphere is missing electrons, so it is positive, and its charge spreads over its surface.

The sphere ends with the sign opposite to the rod's, and the rod loses none of its own charge. The order of steps 3 and 4 matters: remove the rod first, and the electrons flow back up from Earth through the wire, leaving the sphere neutral.

Worked examples

Worked exampleExample 1: charging by friction

A rubber balloon rubbed on a student's hair ends with a charge of −48 nC-48\ \text{nC}. The balloon and hair started neutral. Use e=1.60×10−19 Ce = 1.60\times10^{-19}\ \text{C} and me=9.11×10−31 kgm_e = 9.11\times10^{-31}\ \text{kg}.

(a) How many electrons moved, and in which direction?

(b) What is the net charge of the hair?

(c) By how much did the balloon's mass change?

Show solution

(a) The balloon is negative, so it gained electrons from the hair. The number is

N=∣q∣e=48×10−9 C1.60×10−19 C=3.0×1011 electrons.N = \frac{|q|}{e} = \frac{48\times10^{-9}\ \text{C}}{1.60\times10^{-19}\ \text{C}} = 3.0\times10^{11}\ \text{electrons}.

(b) Take the balloon plus the hair as the system. No charge crossed its boundary, so its net charge stays zero, and the hair has +48 nC+48\ \text{nC}.

(c) The balloon gained 3.0×10113.0\times10^{11} electrons:

Δm=(3.0×1011)(9.11×10−31 kg)=2.7×10−19 kg,\Delta m = (3.0\times10^{11})(9.11\times10^{-31}\ \text{kg}) = 2.7\times10^{-19}\ \text{kg},

far too small to measure, which is why charging never shows up on a scale.

Worked exampleExample 2: a sequence of contacts

Three identical metal spheres on insulating stands carry charges qA=+12 nCq_A = +12\ \text{nC}, qB=−4.0 nCq_B = -4.0\ \text{nC} and qC=0q_C = 0. Sphere A touches sphere B and they are separated. Then B touches C and they are separated.

(a) Find the final charge on each sphere.

(b) During the first contact, how many electrons moved, and from which sphere to which?

Show solution

(a) Identical conducting spheres in contact share their combined charge equally. First contact: A and B together hold +12−4.0=+8.0 nC+12 - 4.0 = +8.0\ \text{nC}, so each leaves with +4.0 nC+4.0\ \text{nC}. Second contact: B and C together hold +4.0+0=+4.0 nC+4.0 + 0 = +4.0\ \text{nC}, so each leaves with +2.0 nC+2.0\ \text{nC}.

Final: qA=+4.0 nCq_A = +4.0\ \text{nC}, qB=+2.0 nCq_B = +2.0\ \text{nC}, qC=+2.0 nCq_C = +2.0\ \text{nC}. Check with conservation: the total was +12−4.0+0=+8.0 nC+12 - 4.0 + 0 = +8.0\ \text{nC} at the start and is 4.0+2.0+2.0=+8.0 nC4.0 + 2.0 + 2.0 = +8.0\ \text{nC} at the end.

(b) B went from −4.0 nC-4.0\ \text{nC} to +4.0 nC+4.0\ \text{nC}, a change of +8.0 nC+8.0\ \text{nC}. Only electrons move, so B lost electrons to A:

N=8.0×10−9 C1.60×10−19 C=5.0×1010 electrons, from B to A.N = \frac{8.0\times10^{-9}\ \text{C}}{1.60\times10^{-19}\ \text{C}} = 5.0\times10^{10}\ \text{electrons, from B to A}.

No positive charge moved onto B. Saying "positive charge flowed from A to B" describes the same change in net charge but the wrong physical carriers.

Worked exampleExample 3: attract, touch, repel (free-response style)

A small neutral foam ball coated with a thin layer of conducting paint hangs from an insulating thread. A plastic rod carrying −20 nC-20\ \text{nC} is brought near the ball without touching it.

(a) The ball swings toward the rod. Explain why a neutral ball is attracted.

(b) The ball touches the rod and is immediately pushed away from it. Explain why.

(c) After the contact, the ball's charge is measured to be −1.5 nC-1.5\ \text{nC}. Calculate how many electrons moved onto the ball, and find the rod's charge now.

(d) With the rod far away, a student touches the ball with a finger, then lets go. The rod is brought back near the ball. Describe and explain what the ball does.

Show solution

(a) The rod's negative charge pushes the ball's free electrons to the far side of its conducting coating, leaving the near side positive. The ball is still neutral, but its positive side is closer to the rod than its negative side. Coulomb's force falls off as 1r2\frac{1}{r^2}, so the attraction on the nearer positive charge is larger than the repulsion on the farther negative charge, and the net force on the ball is toward the rod.

(b) At contact, some excess electrons move from the rod to the ball, so the ball now has a net negative charge, the same sign as the rod. Like charges repel. Only a little charge moves, because the rod is an insulator: only electrons near the touching point can leave it.

(c) Take the rod and ball as the system. No charge crossed its boundary, so its total stays −20 nC-20\ \text{nC}. The ball gained

N=1.5×10−9 C1.60×10−19 C=9.4×109 electrons,N = \frac{1.5\times10^{-9}\ \text{C}}{1.60\times10^{-19}\ \text{C}} = 9.4\times10^{9}\ \text{electrons},

so the rod now has −20−(−1.5)=−18.5 nC-20 - (-1.5) = -18.5\ \text{nC}.

(d) Touching the ball grounds it through the student's body. With no charged object nearby, the excess electrons flow off the ball into the student and on to Earth, and the ball becomes neutral. When the rod returns, the ball is polarized again, exactly as in (a), so it is attracted to the rod once more.

Where students lose points

On the exam

Questions on this topic ask you to predict the sign of an object's final charge after a sequence of steps, draw the charge distribution on a conductor or insulator (plus and minus signs placed where the charge sits), justify a claim in a few sentences, or convert between a charge and a number of electrons, as in Examples 1 to 3. A full justification names the mechanism (transfer of electrons, polarization, grounding) and cites conservation of charge where totals are involved.

Check yourself

  1. Question 1

    You have a rod known to be negatively charged and a small object of unknown charge hanging from a thread. Which observation proves the object is charged?

    1. A

      The object swings toward the rod.

    2. B

      The object swings away from the rod.

    3. C

      The object swings toward the rod and sticks to it.

    4. D

      The object does not move when the rod is far away.

    Show answer

    B

    Only a charged object can be repelled, and repulsion by a negative rod means the object is negative. Attraction (A and C) happens to a neutral object too, because the rod polarizes it and the nearer induced charge is the opposite sign.

  2. Question 2

    Identical metal spheres P and S are touched together and then separated. Afterward, each has charge −q-q. Before contact, P had charge +q+q. What was the charge on S before contact?

    Show answer

    −3q-3q

    After contact the total is −q+(−q)=−2q-q + (-q) = -2q, and conservation says the total before was the same: +q+qS=−2q+q + q_S = -2q, so qS=−3qq_S = -3q.

  3. Question 3

    A positively charged rod is held near a neutral metal sphere on an insulating stand, and the sphere is grounded with a wire. A student then removes the rod first and disconnects the ground wire afterward. What is the sphere's final net charge? Explain.

    Show answer

    Zero.

    With the rod near and the ground connected, electrons flow up from Earth onto the sphere. When the rod is removed while the wire is still connected, nothing holds those extra electrons there, so they flow back to Earth and the sphere ends neutral. To keep a negative charge, the ground must be disconnected before the rod is removed.

  4. Question 4

    A metal sphere with charge −6.0 nC-6.0\ \text{nC} is grounded and becomes neutral. Which statement is correct?

    1. A

      About 3.8×10103.8\times10^{10} electrons flowed from the sphere to Earth, and Earth's net charge changed by −6.0 nC-6.0\ \text{nC}.

    2. B

      About 3.8×10103.8\times10^{10} protons flowed from Earth to the sphere.

    3. C

      The excess charge was destroyed when it reached the ground, so Earth's charge did not change.

    4. D

      About 3.8×10103.8\times10^{10} electrons flowed from the sphere to Earth, and Earth became neutral.

    Show answer

    A

    6.0×10−91.60×10−19=3.75×1010\frac{6.0\times10^{-9}}{1.60\times10^{-19}} = 3.75\times10^{10} electrons left the sphere, and conservation puts that charge on Earth, a change too small to matter for something so large. Choice B has the wrong carriers (protons stay in nuclei), and choice C violates conservation of charge.

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